Hierarchy

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Basic Data
Data Element | RSAN_WB_DST_HIERAGGR |
Short Description | Transformation "Hierarchical Aggregation" |
Data Type
Category of Dictionary Type | Direct Type Entry | |
Type of Object Referenced | No Information | |
Domain / Name of Reference Type | ||
Data Type | STRG | Character String of Variable Length |
Length | 0 | |
Decimal Places | 0 | |
Output Length | 0 | |
Value Table |
Further Characteristics
Search Help: Name | ||
Search Help: Parameters | ||
Parameter ID | ||
Default Component name | ||
Change document | ||
No Input History | ||
Basic direction is set to LTR | ||
No BIDI Filtering |
Field Label
Length | Field Label | |
Short | 10 | Text |
Medium | 20 | Description |
Long | 40 | Description |
Heading | 60 | Description |
Documentation
Use
Hierarchical aggregation is a special type of aggregation; it is the aggregation of hierarchical relationships. The input table contains the information for the hierarchical relationship as well as the aggregating key figures. In addition to aggregation, formulas can also be applied.
Activities
- Specify the hierarchical relationship by selecting Key Field and the field for the Reference to the Predecessor (see example below). Each data record in the input table is then interpreted as a hierarchy node.
- From the available fields, select the fields that are to be changed by the hierarchical aggregation.
- Specify the required aggregation behavior for each aggregation field. The following values are currently supported:
- SUM: The values of the aggregation field are totaled for various levels, by adding all nodes with the same predecessor. The value of the predecessor node is overwritten by this total.
- NOP: No aggregation. You can however change the value of the field using a formula.
- This allows you to perform formula calculations in addition to aggregating a field, if required. To do this, click in the row for the aggregation field, choose "Formula", and create the required formula in the formula builder. You can use all input fields in the formula.
Important: The formula is evaluated after each aggregation step (see example below).
Example
Example 1: A hierarchical relationship exists between each employee and the employer:
Employee Name Superior Overtime
710 Smith 922 2
859 Truman 922 23
922 Miller 212 -
744 Carlson 212 4
212 Wilson - -
Employees Smith and Truman both have Miller as superior. Employee Wilson does not have a superior. The "Employee" column is a key field for the input table and the "Superior" field specifies the relationship to the predecessor.
In this simple example, there is time recording for all employees that are not superiors. To calculate the number of overtime hours for each superior's area, the "Overtime" column is used for aggregation (summation). The results table is as follows:
Employee Name Superior Overtime
710 Smith 922 2
859 Truman 922 23
922 Miller 212 25
744 Carlson 212 4
212 Wilson - 29
Example 2: Assume that overtime is recorded for all employees. You want to calculate the average amount of overtime for each superior's area.
To do this, the input table requires the additional fields "Total Overtime", "Counter", and "Average". You can easily create and fill these auxiliary columns with a transformation of type formula.
Employee Name Superior Overtime Total Average Counter
710 Smith 922 2 2 - 1
859 Truman 922 23 23 - 1
922 Miller 212 11 - - -
744 Carlson 212 4 4 - 1
212 Wilson - 5 - - -
"Total" is required to accommodate the overtime for both the employees and their superior. "Total" is initialized with the overtime of the employees on the lowest level, and "Counter" is initialized with the value 1. The initial values of these fields do not affect the upper levels (superiors), because they are overwritten by the level-by-level aggregation.
For "Total" and "Counter", you set the aggregation behavior to "SUM"; for "Average", you set the aggregation behavior to "NOP".
For "Total", you specify the formula "Total" + "Overtime". During the aggregation for employee "Miller", the overtime for "Miller" and his employees "Smith" and "Truman" is added, that is, "Total" + "Overtime" = 25 + 11 = 36.
For "Average", you specify the formula ("Total" + "Overtime") / ("Counter" + 1). For employee "Miller", the average number of overtime hours is therefore calculated as (25 + 11) / (2 + 1) = 12.
For "Counter", you specify the corresponding formula "Counter" + 1.
The overall result is as follows:
Employee Name Superior Overtime Total Average Counter
710 Smith 922 2 2 - 1
859 Truman 922 23 23 - 1
922 Miller 212 11 36 12 3
744 Carlson 212 4 4 - 1
212 Wilson - 5 45 9 5
History
Last changed by/on | SAP | 20130604 |
SAP Release Created in | 700 |