Hierarchy
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Basic Data
| Data Element | P33_SZV_ALG1 |
| Short Description | Algorithm One for Form SZV |
Data Type
| Category of Dictionary Type | D | Domain |
| Type of Object Referenced | No Information | |
| Domain / Name of Reference Type | CHAR1 | |
| Data Type | CHAR | Character String |
| Length | 1 | |
| Decimal Places | 0 | |
| Output Length | 1 | |
| Value Table |
Further Characteristics
| Search Help: Name | ||
| Search Help: Parameters | ||
| Parameter ID | ||
| Default Component name | ||
| Change document | ||
| No Input History | ||
| Basic direction is set to LTR | ||
| No BIDI Filtering |
Field Label
| Length | Field Label | |
| Short | 10 | Alg. One |
| Medium | 15 | Algorithm One |
| Long | 25 | Algorithm One |
| Heading | 55 | Algorithm One for Form SZV |
Documentation
Definition
Shows the method of seniority calculation.
Use
Dependencies
Example
One of your employees has worked in the following jobs:
Employment Period Company Position
01.09.1973 - 31.08.1974 A -
21.09.1979 - 01.05.1990 B Assistant Clerk
02.05.1990 - 01.09.1990 B Clerk
02.09.1990 - 01.09.1991 B Data Entry Officer
02.09.1991 - 31.12.1998 B Team Assistant
The employee has worked for the following period of time:
(Sum of employment periods in company A) + (Sum of employment periods in company B)
= (31.08.1974 - 01.09.1973) + (31.12.1998 - 21.09.1979)
= (30.-1.1) + (10.3.19)
= 40.2.20 (40 days, 2 months, 20 years)
The employee's seniority is 20 years, 3 months, and 10 days.
Russian legislation stipulates that each time you leave a company, you add one day to the employee's seniority. As such, the employee's seniority is 20 years, 3 months, and 12 days.
History
| Last changed by/on | SAP | 20071120 |
| SAP Release Created in | 600 |